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Home › HSSC Clerk Exams › 2016-11-13 (13 Nov) (Shift-2)
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The least multiple of 7 that leaves a remainder of 4 when divided by 6, 9, 15 and 18 is:

A
74
B
94
C
184
D
364
Correct Option: D

Explanation

The number must leave a remainder of 4 when divided by 6, 9, 15 and 18. Their LCM is 90, so the numbers have the form 90k + 4. Among the options, 364 = 360 + 4, and it is also divisible by 7.

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