Five resistors of 2 Ω, 3 Ω, 4 Ω, 5 Ω and 6 Ω are connected in series to a 6 V battery. The current through the 5 Ω resistor is:
A
3.33 A
B
0.3 A
C
1.2 A
D
120 A
Correct Option:
B
Explanation
In a series circuit, resistances add: 2 + 3 + 4 + 5 + 6 = 20 Ω. Using Ohm's law, I = V/R = 6/20 = 0.3 A. The same current passes through every resistor connected in series, including the 5 Ω resistor.
