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Home › Haryana HSSC Group D Exams › 2018-11-11 (Shift-1)
Question 43 of 90
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If 4 is a zero of the polynomial p(x) = −2x² + 3x + 5k, then the value of k is:

A
4
B
−5
C
5/4
D
−1
Correct Option: A

Explanation

Since 4 is a zero of p(x) = −2x² + 3x + 5k, substitute x = 4: −2(16) + 12 + 5k = 0. This gives −32 + 12 + 5k = 0, or 5k = 20. Therefore, k = 4.

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