Question
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80
Question Palette
Let N be the greatest number that will divide 1305, 4665 & 6905, leaving the same remainder in each case. Then the sum of digits in N is?
Correct Option:
A
Explanation
If the same divisor N leaves the same remainder when dividing all three numbers, N must divide their pairwise differences:
4665-1305=3360, 6905-4665=2240.
Thus:
N=gcd(3360,2240)=1120.
The digit sum is 1+1+2+0=4.
